12b^2-17bc-5c^2=

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Solution for 12b^2-17bc-5c^2= equation:


Simplifying
12b2 + -17bc + -5c2 = 0

Reorder the terms:
-17bc + 12b2 + -5c2 = 0

Solving
-17bc + 12b2 + -5c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3b + -5c)(4b + c) = 0

Subproblem 1

Set the factor '(3b + -5c)' equal to zero and attempt to solve: Simplifying 3b + -5c = 0 Solving 3b + -5c = 0 Move all terms containing b to the left, all other terms to the right. Add '5c' to each side of the equation. 3b + -5c + 5c = 0 + 5c Combine like terms: -5c + 5c = 0 3b + 0 = 0 + 5c 3b = 0 + 5c Remove the zero: 3b = 5c Divide each side by '3'. b = 1.666666667c Simplifying b = 1.666666667c

Subproblem 2

Set the factor '(4b + c)' equal to zero and attempt to solve: Simplifying 4b + c = 0 Solving 4b + c = 0 Move all terms containing b to the left, all other terms to the right. Add '-1c' to each side of the equation. 4b + c + -1c = 0 + -1c Combine like terms: c + -1c = 0 4b + 0 = 0 + -1c 4b = 0 + -1c Remove the zero: 4b = -1c Divide each side by '4'. b = -0.25c Simplifying b = -0.25c

Solution

b = {1.666666667c, -0.25c}

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